Monday 23 March 2015

Q1 Ten individuals are chosen at random, from a normal population and their weights (in kg) are found to be 63, 63, 66, 67, 68, 69, 70, 70, 71 and 71. In the light of this data set, test the claim that the mean weight in population is 66 kg at 5% level of significance.
Ans. Weighted mean = Σwx/Σw
Σ = the sum of (in other words…add them up!).
w = the weights.
x = the value.
To use the formula:
  1. Multiply the numbers in your data set by the weights.
  2. Add the numbers in Step 1 up. Set this number aside for a moment.
  3. Add up all of the weights.
  4. Divide the numbers you found in Step 2 by the number you found in Step 3.
Mean weight = 67.8 kg
Standard deviation = 8.16 kg
Z = (67.9 – 66) /8.16 kg = 0.2328
ZTable(Z) = 0.091      it is 9.1 % significance level.
So the claim that the mean weight in the population is 66 kg at 5% level of significance is WRONG.
Q2 I bought two packets of apples, 25 in each packet. The mean and standard deviation of weights of apples in the first packet are 235 and 3; and the mean and standard deviation for the second packet are 237.5 and 4. Write down the mean and standard deviation formulae for all the fifty
apples and compute them.
Ans. Apples in Each Packets – 25
Mean of First Packets – 235
Standard Daviation of Weight is – 3
Mean of second Packets – 237.5
Standard Daviation of Weight of second packets is – 4
Mean and Standard Deviation for all fifty apples are :
mean = Σwx/Σw
mean of Total = Σ(235 X3 )/Σ(237.5 X 4)
= 705/950
= 0.74
Q3 A consumer research organization tests three brands of tires to see how many miles they can be driven before they should be replaced. One tyre of each brand is tested in each of five types of cars. The results (in thousands of miles) are as follows: (10)
Type of car Brand A Brand B Brand C
I           6 9 4
II         3 2 7
III        2 3 6
IV        8 8 5
V         9 1 8
Compute the ANOVA and interpret your result.
Ans.
STEP 1:
Do the ANOVA table
d.fit <- aov(v~TR,data=d)
summary(d.fit)
Interpretation:
Makes an ANOVA table of the data set
d
, analysing if the factor
TR
has a signi
cant e
ect on
v
.
The function
summary
shows the ANOVA table.
> summary(d.fit)
Df Sum Sq Mean Sq F value Pr(>F)
TR 2 26.1667 13.0833 35.682 0.001097 **
Residuals 5 1.8333 0.3667

Signif. codes: 0 *** 0.001 ** 0.01 * 0.05 . 0.1 1
STEP 2:
Decision:
Interpretation:
Exactly the same as for the “by hand” calculated tableWith
R
we do not have the critical values to a level, but we have the P
Q4 A building has 11 flats. A sample of 4 flats is to be selected using (i) linear systematic sampling and (ii) circular systematic sampling. List all possible samples for each of these cases (10)
separately.
N = 11
n = 4
N/n = 11/4 =2.75      nearest integer = 3
let k = 3
1) Linear systematic sampling
Let i = 1,  sample : 1, 4, 7, 10
i = 2,  sample :   2, 5 , 8 , 11
i =3 ,  sample :    3, 6, 9
2)  Circular systematic sample:
i = 1, sample:  1, 4,7,10
2                2,5,8, 11
3                 3,6,9,1
4                 4,7,10,2
5                 5, 8, 11, 3
6                 6,9,1, 4
7                 7,10,2,5
8                 8,11,3,6
9                 9,1,4,7
10               10,2,5,8
11,              11,3,6,9
Q5 Calculate Probabilities for following situations :
a) There are 1000 pages in a book out of which 100 pages are defective. What is the probability that out of first 50 pages 10 pages will be defective?
AnsProbability Functions
A probability function is a function which assigns probabilities to the values of a random variable.
  • All the probabilities must be between 0 and 1 inclusive
  • The sum of the probabilities of the outcomes must be 1.
If these two conditions aren’t met, then the function isn’t a probability function. There is no requirement that the values of the random variable only be between 0 and 1, only that the probabilities be between 0 and 1.
Probability Distributions
A listing of all the values the random variable can assume with their corresponding probabilities make a probability distribution.
A note about random variables. A random variable does not mean that the values can be anything (a random number). Random variables have a well defined set of outcomes and well defined probabilities for the occurrence of each outcome. The random refers to the fact that the outcomes happen by chance — that is, you don’t know which outcome will occur next.
Here’s an example probability distribution that results from the rolling of a single fair die.
x123456sum
p(x)1/61/61/61/61/61/66/6=1

Mean, Variance, and Standard Deviation
Consider the following.
The definitions for population mean and variance used with an ungrouped frequency distribution
BCS-040_1
Some of you might be confused by only dividing by N. Recall that this is the population variance, the sample variance, which was the unbiased estimator for the population variance was when it was divided by n-1.

What’s even better, is that the last portion of the variance is the mean squared. So, the two formulas that we will be using are:BCS-040_2
BCS-040_3
x123456sum
p(x)1/61/61/61/61/61/66/6 = 1
x p(x)1/62/63/64/65/66/621/6 = 3.5
x^2 p(x)1/64/69/616/625/636/691/6 = 15.1667
The mean is 7/2 or 3.5
The variance is 91/6 – (7/2)^2 = 35/12 = 2.916666…
The standard deviation is the square root of the variance = 1.7078
Q 5 b) A die is tossed twice. Getting an odd number in at least a toss is termed as a success. Find the probability distribution of number of successes. Also find expected number of successes.
Ans. Let S = event that at least an odd number is the outcome of n tosses. = success
Let F = event that no odd number turns out = failure
n =1, then in one toss, probability of an odd number turning out = 3/6 = 1/2
P(S) = 1/2   So P(F) = 1 – 1/2 = 1/2
The tosses of die are independent. The probabilities can be multiplied.
n = 2, two tosses,  P(S) = 1 –  ( P(Failure) in first toss * P(Failure) in 2nd toss)
= 1  – 1/2 * 1/2 = 1 – 1/4 = 3/4
probability distribution is
P(n,X) :   = 0   for n = 0
=  1/2  for  n = 1
=  3/4  for  n = 2
Q 5 c) Find the probability that at most 5 defective fuses will be found in a box of 200, if experience shows that 20% of such fuses are defective.
Ans. 20%of 200=40
so there are 40 fuses which are defective
the probability of finding 5 defectives= 5/40=1/8
Q6 Following data are given for marks in subject A and B in a certain examination :
SUBJECT A     SUBJECT B
MEAN MARKS                       36                               85
STANDARD DEVIATION      11                               8
Coefficient of correlation between A and B = ±0.66
  1. i) Determine the two equations of regression
  2. ii) Calculate the expected marks in A corresponding to 75 marks obtained in B
Ans. i)
The Regression Line
With one independent variable, we may write the regression equation as:
BCS-040_4
Where Y is an observed score on the dependent variable, a is the intercept, b is the slope, X is the observed score on the independent variable, and e is an error or residual.
We can extend this to any number of independent variables:
BCS-040_5
Note that we have k independent variables and a slope for each. We still have one error and one intercept. Again we want to choose the estimates of a and b so as to minimize the sum of squared errors of prediction. The prediction equation is:
BCS-040_6
Finding the values of b is tricky for k>2 independent variables, and will be developed after some matrix algebra. It’s simpler for k=2 IVs, which we will discuss here.
For the one variable case, the calculation of b and a was:
BCS-040_7
At this point, you should notice that all the terms from the one variable case appear in the two variable case. In the two variable case, the other X variable also appears in the equation. For example, Xappears in the equation for b1. Note that terms corresponding to the variance of both X variables occur in the slopes. Also note that a term corresponding to the covariance of X1 and X2 (sum of deviation cross-products) also appears in the formula for the slope.
The equation for a with two independent variables is:
BCS-040_8
This equation is a straight-forward generalization of the case for one independent variable
Ans.6 ii)In a cross between two heterozygous individuals, the offspring would be expected to show a 3 : 1 ratio. For example, in Case 1, three-fourths of the individuals would have red (wild-type) eyes, and one-fourth would have sepia eyes.
If there are 44 offspring, how many are expected to have red eyes?
We expect three-fourths to have red eyes.
If there are 44 offspring, how many are expected to have sepia eyes?

Q7A sample of 900 members has a mean 3.4 cm and standard deviation 2.61 cm. Test whether the sample is from a large population of mean 3.25 cm and standard deviation 2.61 cm. If the population is normal and its mean is unknown, find the 95% confidence interval for population mean.
Ans.
N_s = sample size = 900.         Î¼_s = mean of the sample = 3.4 cm
σ_s = Standard deviation of the sample = 2.61 cm
Population mean Î¼₀ =3.25
Population standard deviation = Ïƒ₀ = 2.61 cm
student’s t = (μ_s – Î¼₀) / [σ_s / √N_s ]
t  = (3.4 – 3.25) * √900 / 2.61 = 1.7241
Find the probability that     -1.7241 <= t <= 1.7241     from the students t distribution table or from a website that calculates these. Here the degrees of freedom (d.f) are 899.  Sample size is 900.
The probability  is 0.915.  Hence,  the sample belongs to the population with a probability 0.915  or  a  confidence level of 91.5%.
The population is normal.  we don’t  know its mean. We know sample size, mean and standard deviation.
Z = (μ_s – Î¼₀) / Ïƒ
Here Ïƒ_s = 2.61  cm
The value z of normal distribution variable Z for which the probability
P( -z < Z < z) = 95% = 0.95   is  z = 1.96
-1.96 * Ïƒ_s <= (μ_s – Î¼₀) <= 1.96 * Ïƒ_s
– 5.1156 <= (μ_s – Î¼₀) <= 5.1156 cm
If we take the value of Î¼_s = 3.4 cm then,
-1.7156  <= Î¼₀ <= 8.5156  cm
Q8 The mean yield for one acre plot is 662 kg with a s.d. 32 kg. Assuming normal distribution, how many one acre plot in a batch of 1000 plots would your expect to have yield between 600 and 750 kg.
Ans.The mean yield for one acre plot is 662 kg with a s.d 32kg .assuming normal distribution how many one acre plot in a batch of 1000 plots would your expect to have yield between 600 and 750 kg.

Saturday 28 February 2015

(i) A Palindrome is a string that reads the same forward and backward. Write an algorithm for determining whether a string of characters is palindrome.
Solution:-
C program to check whether it is a palindrome and also find the length of string
1. #include <stdio.h>
2. #include <string.h>
3.  
4. void main()
5. {
6.     char string[25], reverse_string[25] = {'\0'};
7.     int i, length = 0, flag = 0;
8.  
9.     printf("Enter a string \n");
        gets(string);
    /*  keep going through each character of the string till its end */
   for (i = 0; string[i] != '\0'; i++)
    {
        length++;
    }
    printf("The length of the string '%s' = %d\n", string, length);
    for (i = length - 1; i >= 0 ; i--)
    {
        reverse_string[length - i - 1] = string[i];
    }
   /*  Check if the string is a Palindrome */
    for (flag = 1, i = 0; i < length ; i++)
    {
        if (reverse_string[i] != string[i])
            flag = 0;

    }
    if (flag == 1)
       printf ("%s is a palindrome \n", string);
    else
       printf("%s is not a palindrome \n", string);
}
Output:-
Enter a string
  how  are you
The length of the string 'how  are you' = 12
how  are you is not a palindrome
-------------------------------------------------------------------
 Enter a string
   madam
 The length of the string 'madam' = 5
 madam is a palindrome
Algorithm:-
step 1 : start

step 2 : Declare variables char_string[25], reverse_string[25]
                    int i, length = 0, flag = 0;

step 3 : read value string.

step 4 : for (i = 0; string[i] != '\0'; i++)
         length++
step 5 : display 'the length of string =', string, length

step 6 : for (i = length - 1; i >= 0 ; i--)
        do reverse_string[length - i - 1] = string[i]
          /*  Check if the string is a Palindrome */

step 7 : for (flag = 1, i = 0; i < length ; i++)
                  if revers_string[i] ! = string[i]
                           do flag = 0
                        if flag == 1
                         display string is palindrome.
                         else 
                         display string is not palindrome.

step 8 : stop.
(ii) Find the largest number in an array and count a number of comparison operations as well as running time complexity of each statement and total complexity of the problem.
Solution:-
#include <stdio.h>
int main() {

    int i,n, count = 0;
    float arr[100];
    printf("Enter total number of elements(1 to 100): ");
    scanf("%d",&n);
    printf("\n");
    for(i=0;i<n;++i)  /* Stores number entered by user. */
    {
       printf("Enter Number %d: ",i+1);
       scanf("%f",&arr[i]);
    }

    for(i=1;i<n;++i)  /* Loop to store largest number to arr[0] */
    {
       if(arr[0]<arr[i]) /* Change < to > if you want to find smallest element*/
       {       
       count++;
       }
           arr[0]=arr[i];
    }
    printf("Largest element = %.2f \n",arr[0]);
    printf(“the number of comparison %d”, count);    
    return 0;
       getch();
}
Output:-
largestnum

Time Complexity of AlgorithmsTime complexity of an algorithm signifies the total time required by the program to run to completion. The time complexity of algorithms is most commonly expressed using the big O NotationTime Complexity is most commonly estimated by counting the number of elementary functions performed by the algorithm.
Calculating the Complexity
Now lets tap onto the next big topic related to Time complexity, which is How to Calculate Time Complexity. It becomes very confusing some times, but we will try to explain it in the simplest way.
Now the most common metric for calculating time complexity is Big O notation. This removes all constant factors so that the running time can be estimated in relation to N, as N approaches infinity. In general you can think of it like this:
statement;
Above we have a single statement. Its Time Complexity will be Constant. The running time of the statement will not change in relation to N
for(i=0; i &lt; N; i++)
              {
                     statement;
               }
The time complexity for the above algorithm will be Linear. The running time of the loop is directly proportional to N. When N doubles, so does the running time.
for(i=0; i &lt; N; i++)
    {
        for(j=0; j &lt; N;j++)
            {
              statement;
             }
    }
This time, the time complexity for the above code will be Quadratic. The running time of the two loops is proportional to the square of N. When N doubles, the running time increases by N * N.
(iii) Write a programme which interchanges the values the variable using only assignment operations. What is the minimum number of assignments operations required?
Solution:-
#include <stdio.h>
#include <string.h> 
/* Function Prototype */

void swap(int*, int *);
void main()
{
    int num1, num2;
printf("\nEnter two numbers:");
scanf("%d %d", &num1, &num2);
printf("\nThe numbers before swapping are Number1= %d Number2 = %d", num1, num2);
swap(&num1, &num2);   /* Call by Reference to function swap */
printf("\nThe numbers after swapping are Number1= %d Number2 = %d", num1, num2);

}
/* Code to swap two numbers using Assignment operator */
void swap(int *x, int *y)
  {
    *x = *x ^= *y;
    *y = *y ^= *y;
    *x = *x ^= *y;
}
Output:-
numsapThe minimum number of operator assigned is six because as we can see in the void swap function in that we used assignment operator six time to swap the value of num1 and num2.
(iv) Write a programme to do bubblesort to sort an array X={10,5,7,8,3,6,4,14} showing the
list obtained at each step. Also count no. of comparison operations in the programme
Solution:
#include <stdio.h>
int printAarray(int arr[]){
printf("\n Array at this stage = ");
for(int i=0; i<8; i++){
if(i==7){
printf("%d", arr[i]);
}else{
printf("%d, ", arr[i]);
}
}
printf("\n");
}
int main()
{
int X[]={10,5,7,8,3,6,4,14};
int n=8, c, d, swap, comp=0;
for (c = 0 ; c < ( n - 1 ); c++)
{
for (d = 0 ; d < n - c - 1; d++)
{
if (X[d] > X[d+1]) /* For decreasing order use < */
{
comp++;
swap = X[d];
X[d] = X[d+1];
X[d+1] = swap;
printAarray(X);
}
printAarray(X);
}
printAarray(X);
}
printf(" \n\n Sorted list in ascending
order:\n===================================\n");
for ( c = 0 ; c < n ; c++ ){
printf(" %d\n", X[c]);
}
printf("===================================\n Total Comparisons =
%d\n", comp);
return 0;
}
(v) Write a programme to find multiplication of matrices of order 4*4 and find the total
number of comparison, total no. of assignments, total number of multiplications and total
number of addition operations required in the programme.
Solution:
#include <stdio.h>
int main()
{
int a[4][4]={
{1,2,3,4},
{5,6,7,8},
{9,1,2,3},
{3,4,5,6}
} ;
int b[4][4]={
{1,2,3,4},
{5,6,7,8},
{9,1,2,3},
{3,4,5,6}
} ;
int c[4][4];
int sum, total_comparisons=0, total_assignments=0,
total_multiplications=0, total_additions=0;
//Multiplication Logic
for (int i = 0; i <= 3; i++) {
total_comparisons++;
for (int j = 0; j <= 3; j++) {
total_comparisons++;
sum = 0;
total_assignments++;
for (int k = 0; k <= 3; k++) {
sum = sum + a[i][k] * b[k][j];
total_comparisons++;
total_multiplications++;
total_additions++;
total_assignments++;
}
c[i][j] = sum;
total_assignments++;
}
}
printf("\nMultiplication Of Two Matrices :
\n================================\n");
for (i = 0; i <= 3; i++) {
for (int j = 0; j <= 3; j++) {
printf(" %d ", c[i][j]);
}
printf("\n");
}
printf("\nTotal Numbers (for logic only not for printing):
\n===============================================\n");
printf("\nTotal comparison \t:\t %d\n", total_comparisons);
printf("\nTotal assignments \t:\t %d\n",
total_assignments);
printf("\nTotal multiplications \t:\t %d\n",
total_multiplications);
printf("\nTotal addition \t\t:\t %d\n", total_additions);
return 0;
}
Question 1: Create a web site for a School consisting of the following pages:
a) The Home page should consists of four areas containing the following information:
  • Header area containing the logo, name of the school and a photograph of the school. Make sure that you use a good picture format.
  • Left area containing the links to other pages – these links should include -
  • About us, Academics, Infrastructure, Contact us and Feedback.
  • The Content area should display a table showing list of upcoming events of the School along with dates.
  • The Footer area should display the copyright information and current date and time.
Note:- You need to make sure that the Header and Footer area is same across all the pages of the website.
b) About us page should give information about the Objectives, values and beliefs of the school, preferable in some structured format. You may use lists or tables for the same.
c) Academics page lists details about the teachers and the past activities of the school.
d) Infrastructure page should highlighting the available resources of the school.
e) Contact us page should provide information about the school address and contact details
f) Feedback page should have a feedback form consisting of text box, radio buttons, list boxes etc. This page should get the information from the site visitors about various aspects of schools website. You must use JavaScript to check that all the required fields are entered by the visitor.
g) Write a program using VBscipt that adds only diagonal elements of two matrices. The program should be efficient.
Solution: a web site for a School
a)
<code>
< HTML>
< frameset rows=”21%,*” >
< frame name=”topframe” src=”header.html” frameborder=”0″ scrolling=”no”/ >
< frameset rows=”83%,*” >
< frameset cols=”15%,*” >
< frame name=”left” src=”links.html” frameborder=”0″ scrolling=”no”/ >
< frame name=”centre” src=”home.html” frameborder=”0″/ >
</ frameset >
< frame name=”lowerframe” src=”footer.html” frameborder=”0″ scrolling=”no”/ >
</ frameset >
</ frameset >
</ HTML>
</code>

For Header Area:   Header.html
<code>
<html>
<head>
<title>MCSL 016 Assignment</title>
<meta http-equiv=”Content-Type” content=”text/html; charset=iso-8859-1″>
<style type=”text/css”>
.style2 {
font-size: 12px;
font-family: Verdana, Arial, Helvetica, sans-serif;
color: #00CC00;
}
.style4 {font-size: 10px; color: #000000; }
.style5 {font-family: Verdana, Arial, Helvetica, sans-serif}
.style6 {
font-size: 27px;
color: #FF0000;
}
.style10 {font-size: 10px; color: #9933FF; }
body {
background-color: #333333;
}
</style>
</head>
<body>
<table align=”left”>
<tr>
<td> <img src=”logo.jpg” alt=”logo” width=”80px” height=”80px”/>
<td>
Indian Education Society’s
NEW ENGLISH SCHOOL
Govt Colony, Bandra (E)
MUMBAi- 400051
</td>
<td> <img src=”logo.jpg” alt=”logo” width=”80px” height=”80px”/>
</tr>
<tr>
</table>
<table align=”right”>
<td> <img src=”school.jpeg” width=”400px” height=”80px”/> </td>
</td>
<tr>
<td>  Quick Links :
<select name=”ddlist”>
<option> Home</option>
<option> About Us</option>
<option> Academics</option>
<option> Infrastructure</option>
<option> Contact Us</option>
<option> Feedback</option>
</select> </td>
</tr>
</tr>
</table>
</body>
</html>
</code>
For Left Area:  Links.html
<code>
<HTML >
<HEAD >
<TITLE > </TITLE >
<BODY bgcolor=”lightblue” >
<table align=”left” >
<tr > <td > </td ></tr >
<tr >
<td > <a href=”home.html” target=”centre” > Home</a > </td >
</tr >
<tr > <td > </td ></tr >
<tr >
<td > <a href=”about.html” target=”centre” > About us</a > </td >
</tr >
<tr > <td > </td ></tr >
<tr >
<td > <a href=”academic.html” target=”centre” > Academics</a > </td >
</tr >
<tr > <td > </td ></tr >
<tr >
<td > <a href=”infra.html” target=”centre” > Infrastructure</a > </td >
</tr >
<tr > <td > </td ></tr >
<tr >
<td > <a href=”contact.html” target=”centre” > Contact us</a > </td >
</tr >
<tr > <td > </td ></tr >
<tr >
<td > <a href=”feedback.html” target=”centre” > Feedback</a > </td >
</tr >
</table >
</BODY >
</HTML >
</code>
For Content Area:  Home.html
<code>
<HTML >
<HEAD >
<TITLE > New Document </TITLE >
</HEAD >
<BODY bgcolor=”lightgreen” >
Home Page
<center > <h1 > <u > Welcome To New English School Website</u > </h1 > <center >
<table align=”center” >
<tr >
<tr > <img src=”big_school.jpg” alt=”Image” width=”500px” height=”250px”/ > </td >
</tr >
</table >
<table width=”737″ border=”0″>
<table width=”100%” border=”0″ align=”right” cellpadding=”0″ cellspacing=”0″>
<tr>
<td><p align=”center”><strong><u>UPCOMING EVENTS</u><br><br>EXAMINATION SCHEDULE FOR HALF-YEARLY EXAMINATION<br>
</strong><strong>Aug 2014 </strong></p>
<table align=”center” width=”571″ border=”1″>
<tr>
<td width=”70″><div align=”center”>
<div align=”center”>Class/Date</div>
</div></td>
<td width=”45″><div align=”center”> 1 </div></td>
<td width=”46″><div align=”center”> 4 </div></td>
<td width=”47″><div align=”center”> 7 </div></td>
<td width=”53″><div align=”center”> 10 </div></td>
<td width=”50″><div align=”center”><span class=”style28″>13 </div></td>
<td width=”52″><div align=”center”><span class=”style28″>16 </div></td>
<td width=”48″><div align=”center”> 19 </div></td>
<td width=”51″><div align=”center”><span class=”style28″>22 </div></td>
<td width=”45″><div align=”center”><span class=”style28″>25 </div></td>
</tr>
<tr>
<td><div align=”center”>
<div align=”center”><strong>I</strong></div>
</div></td>
<td><div align=”center”><span class=”style18″>Bengali </div></td>
<td><div align=”center”><span class=”style18″>English </div></td>
<td><div align=”center”><span class=”style18″>Maths </div></td>
<td><div align=”center”><span class=”style18″>Drawing </div></td>
<td><div align=”center”><span class=”style18″>Science </div></td>
<td><div align=”center”> Work Edn  </div></td>
<td><div align=”center”> Phy. Edn  </div></td>
<td><div align=”center”> * </div></td>
<td><div align=”center”> * </div></td>
</tr>
<tr>
<td><div align=”center”>
<div align=”center”><strong>II</strong></div>
</div></td>
<td><div align=”center”><span class=”style18″>Maths </div></td>
<td><div align=”center”><span class=”style18″>English </div></td>
<td><div align=”center”> Science </div></td>
<td><div align=”center”><span class=”style18″>Bengali </div></td>
<td><div align=”center”>  </div></td>
<td><div align=”center”> Phy. Edn </div></td>
<td><div align=”center”> * </div></td>
<td><div align=”center”> Work Edn </div></td>
<td><div align=”center”> * </div></td>
</tr>
<tr>
<td><div align=”center”>
<div align=”center”><strong>III</strong></div>
</div></td>
<td><div align=”center”> * </div></td>
<td><div align=”center”><span class=”style18″>Maths </div></td>
<td><div align=”center”><span class=”style18″>Science </div></td>
<td><div align=”center”><span class=”style18″>English </div></td>
<td><div align=”center”><span class=”style18″>Bengali </div></td>
<td><div align=”center”> * </div></td>
<td><div align=”center”> Phy. Edn </div></td>
<td><div align=”center”> * </div></td>
<td><div align=”center”> Work Edn </div></td>
</tr>
<tr>
<td><div align=”center”>
<div align=”center”><strong>IV</strong></div>
</div></td>
<td><div align=”center”> Phy. Edn </div></td>
<td><div align=”center”> * </div></td>
<td><div align=”center”><span>English </div></td>
<td><div align=”center”> * </div></td>
<td><div align=”center”><span class=”style18″>Maths </div></td>
<td><div align=”center”><span class=”style18″>Bengali </div></td>
<td><div align=”center”><span class=”style18″>Science </div></td>
<td><div align=”center”> * </div></td>
<td><div align=”center”> Work Edn </div></td>
</tr>
<tr>
<td><div align=”center”>
<div align=”center”><strong>V</strong></div>
</div></td>
<td><div align=”center”><span class=”style18″>Science </div></td>
<td><div align=”center”> Work Edn </div></td>
<td><div align=”center”> * </div></td>
<td><div align=”center”><span class=”style18″>Bengali </div></td>
<td><div align=”center”> * </div></td>
<td><div align=”center”><span class=”style18″>English </div></td>
<td><div align=”center”> Phy. Edn </div></td>
<td><div align=”center”><span class=”style18″>Maths </div></td>
<td><div align=”center”> * </div></td>
</tr>
<tr>
<td><div align=”center”>
<div align=”center”><strong>VI</strong></div>
</div></td>
<td><div align=”center”> * </div></td>
<td><div align=”center”><span class=”style18″>Maths </div></td>
<td><div align=”center”><span class=”style18″>Science </div></td>
<td><div align=”center”> Phy. Edn </div></td>
<td><div align=”center”><span class=”style18″>Bengali </div></td>
<td><div align=”center”><span class=”style18″>History </div></td>
<td><div align=”center”><span class=”style18″>English </div></td>
<td><div align=”center”><span class=”style18″>Biology </div></td>
<td><div align=”center”> Work Edn </div></td>
</tr>
<tr>
<td><div align=”center”>
<div align=”center”><strong>VII</strong></div>
</div></td>
<td><div align=”center”> Phy. Edn </div></td>
<td><div align=”center”><span class=”style18″>Physics </div></td>
<td><div align=”center”><span class=”style18″>Bengali </div></td>
<td><div align=”center”><span class=”style18″>Chem </div></td>
<td><div align=”center”><span class=”style18″>Maths </div></td>
<td><div align=”center”> Work Edn </div></td>
<td><div align=”center”> Economics </div></td>
<td><div align=”center”><span class=”style18″>English </div></td>
<td><div align=”center”><span class=”style18″>History </div></td>
</tr>
<tr>
<td><div align=”center”>
<div align=”center”><strong>VIII</strong></div>
</div></td>
<td><div align=”center”><span class=”style18″>Socio </div></td>
<td><div align=”center”> Phy. Edn </div></td>
<td><div align=”center”><span class=”style18″>Maths </div></td>
<td><div align=”center”> Work Edn </div></td>
<td><div align=”center”><span class=”style18″>Physics </div></td>
<td><div align=”center”><span class=”style18″>Chem </div></td>
<td><div align=”center”><span class=”style18″>Bengali </div></td>
<td><div align=”center”><span class=”style18″>Economics </div></td>
<td><div align=”center”><span class=”style18″>English </div></td>
</tr>
<tr>
<td><div align=”center”>
<div align=”center”><strong>IX</strong></div>
</div></td>
<td><div align=”center”><span class=”style18″>Biology </div></td>
<td><div align=”center”> Work Edn </div></td>
<td><div align=”center”><span class=”style18″>History </div></td>
<td><div align=”center”><span class=”style18″>Chem </div></td>
<td><div align=”center”><span class=”style18″>Maths </div></td>
<td><div align=”center”> Bengali </div></td>
<td><div align=”center”> Phy. Edn </div></td>
<td><div align=”center”><span>English </div></td>
<td><div align=”center”><span class=”style18″>Physics </div></td>
</tr>
<tr>
<td><div align=”center”>
<div align=”center”><strong>X</strong></div>
</div></td>
<td><div align=”center”><span class=”style18″>Biology </div></td>
<td><div align=”center”><span class=”style18″>Economics </div></td>
<td><div align=”center”> Work Edn </div></td>
<td><div align=”center”><span class=”style18″>Bengali </div></td>
<td><div align=”center”><span class=”style18″>Maths </div></td>
<td><div align=”center”><span class=”style18″>Physics </div></td>
<td><div align=”center”><span class=”style18″>English </div></td>
<td><div align=”center”> Phy. Edn </div></td>
<td><div align=”center”> Biology </div></td>
</tr>
<tr>
<td><div align=”center”>
<div align=”center”><strong>XI</strong></div>
</div></td>
<td><div align=”center”><span class=”style18″>Chem </div></td>
<td><div align=”center”><span class=”style18″>Economics </div></td>
<td><div align=”center”><span class=”style18″>Bengali </div></td>
<td><div align=”center”><span class=”style18″>Biology </div></td>
<td><div align=”center”><span class=”style18″>Socio </div></td>
<td><div align=”center”><span class=”style18″>English </div></td>
<td><div align=”center”><span class=”style18″>Statistics </div></td>
<td><div align=”center”><span class=”style18″>Maths </div></td>
<td><div align=”center”><span class=”style18″>Physics </div></td>
</tr>
<tr>
<td><div align=”center”>
<div align=”center”><strong>XII</strong></div>
</div></td>
<td><div align=”center”><span class=”style18″>Bengali </div></td>
<td><div align=”center”><span class=”style18″>Biology </div></td>
<td><div align=”center”><span class=”style18″>Socio </div></td>
<td><div align=”center”><span class=”style18″>Maths </div></td>
<td><div align=”center”><span class=”style18″>English </div></td>
<td><div align=”center”><span class=”style18″>Statistics </div></td>
<td><div align=”center”><span class=”style18″>Physics </div></td>
<td><div align=”center”><span class=”style18″>Economics </div></td>
<td><div align=”center”><span class=”style18″>Chem </div></td>
</tr>
</table>
</BODY >
</HTML >
</code>
For Footer Area:  <strong>Footer.html</strong>
<code>
<HTML >
<HEAD >
<TITLE > New Document </TITLE >
</HEAD >
<script language=”vbscript” >
sub getCurrentDateTime()
dim daydate,daytime
daydate=FormatDateTime(Date(),1)
dtime=Hour(Now)
document.form1.txtdatetime.value=CStr(daydate)+” “+CStr(Time)
end sub
</script>
<BODY bgcolor=”lightblue” onLoad=”getCurrentDateTime()” >
<form name=”form1″ onLoad=”getCurrentDateTime()” >
<p><center><u>ALL RIGHT RESERVED.</u><center >
Copyright @ 2014, New English School, Bandra. <br />
<table>
<tr> </tr>
<tr> <td> Current Date &amp; Time:</td> <td> <input type=”text” name=”txtdatetime” size=”30″ /> </td> <td> </td>
<tr> </tr>
</table>
<strong><a href=”home.html”>Home</a> / <a href=”about.html”>About Us</a> / <a href=”academic.html”>Academics</a> / <a href=”infra.html”>Infrastucture</a>/ <a href=”contact.html”>Contact Us</a> </strong></p>
</form>
</BODY >
</HTML >
</code>
b)About us page should give information about the Objectives, values and beliefs of the school, preferable in some structured format. You may use lists or tables for the same.
For About Us Page:  About.html
<code>
<html>
<head>
<title>IES New English School, Bandra , Mumbai</title>
</head>
<body bgcolor=”lightgreen” >
About us Page
<div>
<h1>ABOUT US</h1>
<table width=”581″ border=”0″>
<tr>
<td width=”700″><table width=”550″ border=”0″ align=”center” cellpadding=”0″ cellspacing=”0″>
<tbody>
<tr>
<th height=”117″ scope=”col”><p align=”center”>Indian Education Society</p>
<p align=”justify”>The Indian Education Society was founded in 1912 by a tiny band of young and dedicated College teachers who gave the best years of their lives to the society and its Colleges. They were S.V. Nabar, B.N. Vaidya, V.N.SuIe, P.Y. Patkar and |M.D.Harne. The little seed these stalwarts sowed grew into a mighty tree with several branches, Colleges and colleges. In the later period, the Indian Education Society was served brilliantly by Manik Lotlikar and Padmakar Dhamdhere. Undertheir care and tutelage the society developed into an institution managing over sixty Colleges, a junior college and two professional colleges – a College of Management and a College of Architecture. The Colleges of the I.E.S. have been a nursery out of which have blossomed enormous number of persons with varied talents. Its Colleges have produced some of the leading scientists and researchers, scholars and teachers, engineers and doctors, brave members of the armed forces, cricketers and swimmers, theatre and film personalities as well as the first Indian idol! The Indian Education Society is committed to serve the community with the best kind of education. It has taken innovative steps in the field of education like e – learning, encouragement of technical education at the College level, digitalizing of libraries, introduction of new streams like the ICSE, etc. The Society has also initiated the process of accreditation of its Colleges by the Quality Council of India begining with the NES Campus in Bandra East. In establishing a junior college the IES affirms that it would provide the best facilities and resources to its students. In keeping with the high standard the IES has maintained in the past, we hope to have a junior college which would become soon the first choice of our students. The Indian Education Society believes that in cooperation with the heads of our institutions and teachers and parents / guardians and students, we can scale still greater heights of excellence and educate our young to become worthy citizens of our country.</p>
<div align=”left”>
<p> </p>
<table width=”377″ height=”12″ border=”0″ cellpadding=”0″ cellspacing=”0″>
<tbody>
<tr>
<td valign=”top”> </td>
<td colspan=”2″ valign=”top”><p>Indian Education Society <br />
Raja Shivaji Vidyasankul, Hindu Colony, Dadar, <br />
Mumbai 400 014. Tel. N0. 6137 9595</p>
<p>Governing Council</p></td>
</tr>
<tr>
<td width=”119″ valign=”top”> </td>
<td width=”201″ valign=”top”><p>A. B. Vaidya</p></td>
<td width=”323″ valign=”top”><p>President</p></td>
</tr>
<tr>
<td width=”119″ valign=”top”> </td>
<td width=”201″ valign=”top”><p>Manohar D. Lotlikar</p></td>
<td width=”323″ valign=”top”><p>Vice President and Chief Executive Officer</p></td>
</tr>
<tr>
<td width=”119″ valign=”top”> </td>
<td width=”201″ valign=”top”><p>Amol P. Dhamdhere</p></td>
<td width=”323″ valign=”top”><p>Vice President</p></td>
</tr>
<tr>
<td width=”119″ valign=”top”> </td>
<td width=”201″ valign=”top”><p>Achala Joshi</p></td>
<td width=”323″ valign=”top”><p>Trustee</p></td>
</tr>
<tr>
<td width=”119″ valign=”top”> </td>
<td width=”201″ valign=”top”><p>Satish M. Lotlikar</p></td>
<td width=”323″ valign=”top”><p>Trustee</p></td>
</tr>
<tr>
<td width=”119″ valign=”top”> </td>
<td width=”201″ valign=”top”><p>Satish R. Nayak</p></td>
<td width=”323″ valign=”top”><p>Trustee</p></td>
</tr>
<tr>
<td width=”119″ valign=”top”> </td>
<td width=”201″ valign=”top”><p>Shailendra V. Gharse</p></td>
<td width=”323″ valign=”top”><p>Member</p></td>
</tr>
<tr>
<td width=”119″ valign=”top”> </td>
<td width=”201″ valign=”top”><p>V. K. Sinha</p></td>
<td width=”323″ valign=”top”><p>Member</p></td>
</tr>
<tr>
<td width=”119″ valign=”top”> </td>
<td width=”201″ valign=”top”><p>Meenal Mohadikar</p></td>
<td width=”323″ valign=”top”><p>Member</p></td>
</tr>
<tr>
<td width=”119″ valign=”top”> </td>
<td width=”201″ valign=”top”><p>Suhas G. Rege</p></td>
<td width=”323″ valign=”top”><p>Member</p></td>
</tr>
<tr>
<td width=”119″ valign=”top”> </td>
<td width=”201″ valign=”top”><p>Shaunak Satpute</p></td>
<td width=”323″ valign=”top”><p>Member</p></td>
</tr>
<tr>
<td width=”119″ valign=”top”> </td>
<td width=”201″ valign=”top”><p>Gajanan Samant</p></td>
<td width=”323″ valign=”top”><p>Member</p></td>
</tr>
<tr>
<td width=”119″ valign=”top”> </td>
<td width=”201″ valign=”top”><p>Sagar Sule</p></td>
<td width=”323″ valign=”top”><p>Member</p></td>
</tr>
<tr>
<td width=”119″ valign=”top”> </td>
<td width=”201″ valign=”top”><p>Rajeev Joshi</p></td>
<td width=”323″ valign=”top”><p>Member</p></td>
</tr>
<tr>
<td width=”119″ valign=”top”> </td>
<td width=”201″ valign=”top”><p>Geetanjali Desai</p></td>
<td width=”323″ valign=”top”><p>Heads’ Representative</p></td>
</tr>
<tr>
<td width=”119″ valign=”top”> </td>
<td width=”201″ valign=”top”><p>Vaishali K. More</p></td>
<td width=”323″ valign=”top”><p>Supervisors’ Representative</p></td>
</tr>
<tr>
<td width=”119″ valign=”top”> </td>
<td width=”201″ valign=”top”><p>Rajani Mhaisalkar</p></td>
<td width=”323″ valign=”top”><p>Teachers’ Representative</p></td>
</tr>
</tbody>
</table>
</div>
<blockquote>
<p align=”left”><strong>INDIAN EDUCATION SOCIETY<br />
New English School </strong><br />
</p>
<p align=”left”> V. K. Sinha <strong>Chairman</strong></p>
<p align=”left”> Amol Dhamdhere</p>
<p align=”left”> Satish R. Nayak</p>
<p align=”left”> Gajanan V. Samant</p>
<p align=”left”> Shailendra V. Gharse</p>
<p align=”left”> Vikram Karandikar</p>
<p align=”left”> Lakshmi Jayakar</p>
<p align=”left”>Dr. Mulwad Vinata</p>
<p align=”left”>Bharati M. Hajari <strong>Convenor</strong></p>
<p align=”left”><br />
INDIAN EDUCATION SOCIETY<br />
New English School
</p>
<p align=”left”>Government Servants Colony, Near Kherwadi Police Station,<br />
Bandra ( E) , Mumbai 400051.</p>
</blockquote>
<p align=”left”> </p>
<p>V. K. Sinha Bharati M. Hajari</p>
<p>Chairman Principal</p>
</th>
</tr>
</tbody>
</table>
<br /></td>
</tr>
</table>
<p>&amp;nbsp;</p>
</div>
</body>
</html>
</code>
c)Academics page lists details about the teachers and the past activities of the school.
For Academics Page:  Academic.html
<code>
<html><head> <title>IES New English School, Bandra , Mumbai</title> </head> <body bgcolor=”lightgreen” > Academic’s Page <div> <h1>Academic </h1> <table width=”596″ border=”0″> <tr> <td width=”590″><table width=”539″ height=”47″ border=”0″ align=”center” cellpadding=”0″ cellspacing=”0″> <tbody> <tr> <th width=”520″ height=”45″ scope=”col”><p align=”left”>    <span class=”style23″>Admission-  <br /> <br /> 1] Admission is open to all irrespective caste, creed and religion.<br /> 2] Applications are available in the office<br /> 3] The necessary documents such as L.C, latest progress report from the previous school etc. should be attached with the form.<br /> 4] Admissions will be confirmed only after the interview of the student and payment of fees.    </p> </th> </tr> </tbody> </table> <p align=”center”><strong><u>ACHIEVEMENTS IN SPORTS</u></strong></p> <div align=”center”> <table border=”1″ cellspacing=”0″ cellpadding=”0″ align=”left”> <tr> <td width=”81″ valign=”top”><br /> Year </td> <td width=”111″ valign=”top”><p>Competition</p></td> <td width=”115″ valign=”top”><p>Organizer</p></td> <td width=”234″ valign=”top”><p>Result</p></td> </tr> <tr> <td width=”81″ valign=”top”><p>2009</p></td> <td width=”111″ valign=”top”><p>Carrom</p></td> <td width=”115″ valign=”top”><p>District Krida Adhikari</p></td> <td width=”234″ valign=”top”><p>Kadam Sheyas- I Prize &amp;amp; gold medal<br /> Gaddam Neha-II Prize &amp;amp; silver medal<br /> The school received Runner Up award and bagged a Trophy</p></td> </tr> <tr> <td width=”81″ valign=”top”><p>&amp;nbsp;</p></td> <td width=”111″ valign=”top”><p>Cricket</p></td> <td width=”115″ valign=”top”><p>Khichadiya</p></td> <td width=”234″ valign=”top”><p>Runner Up Award</p></td> </tr> <tr> <td width=”81″ valign=”top”><p>&amp;nbsp;</p></td> <td width=”111″ valign=”top”><p>&amp;nbsp;</p></td> <td width=”115″ valign=”top”><p>Air India</p></td> <td width=”234″ valign=”top”><p>Runner Up Award</p></td> </tr> <tr> <td width=”81″ valign=”top”><p>&amp;nbsp;</p></td> <td width=”111″ valign=”top”><p>&amp;nbsp;</p></td> <td width=”115″ valign=”top”><p>I. E. S</p></td> <td width=”234″ valign=”top”><p>Won final and received a Trophy<br /> Pawar Dipesh declared the best player and received a gold medal</p></td> </tr> <tr> <td width=”81″ valign=”top”><p>&amp;nbsp;</p></td> <td width=”111″ valign=”top”><p>Kho-Kho</p></td> <td width=”115″ valign=”top”><p>Mumbai Sports</p></td> <td width=”234″ valign=”top”><p>Won the final</p></td> </tr> <tr> <td width=”81″ valign=”top”><p>2010</p></td> <td width=”111″ valign=”top”><p> Kabaddi</p></td> <td width=”115″ valign=”top”><p>Vand Mataram Foundation</p></td> <td width=”234″ valign=”top”><p>I Prize &amp;amp; Trophy</p></td> </tr> <tr> <td width=”81″ valign=”top”><p>&amp;nbsp;</p></td> <td width=”111″ valign=”top”><p>Kho-Kho</p></td> <td width=”115″ valign=”top”><p>I.E.S</p></td> <td width=”234″ valign=”top”><p>Trophy</p></td> </tr> <tr> <td width=”81″ valign=”top”><p> </p></td> <td width=”111″ valign=”top”><p>Cricket (Vinu Mankad)</p></td> <td width=”115″ valign=”top”><p>District Krida Adhikari</p></td> <td width=”234″ valign=”top”><p>Runner Up Award</p></td> </tr> <tr> <td width=”81″ valign=”top”><p>&amp;nbsp;</p></td> <td width=”111″ valign=”top”><p>Carrom</p></td> <td width=”115″ valign=”top”><p>I.E.S</p></td> <td width=”234″ valign=”top”><p>Acharya Raj- I Prize and Gold medal<br /> Kale Mayuri- I Prize &amp;amp; Gold medal</p></td> </tr> <tr> <td width=”81″ valign=”top”><p>&amp;nbsp;</p></td> <td width=”111″ valign=”top”><p>Chess</p></td> <td width=”115″ valign=”top”><p>I.E.S</p></td> <td width=”234″ valign=”top”><p> Chaudary Vaibhavi- I Prize &amp;amp; Gold medal</p></td> </tr> <tr> <td width=”81″ valign=”top”><p>2011</p></td> <td width=”111″ valign=”top”><p>Disrict level cricket </p></td> <td width=”115″ valign=”top”><p>District Krida Adhikari</p></td> <td width=”234″ valign=”top”><p>Runner Up Award</p></td> </tr> <tr> <td width=”81″ valign=”top”><p>&amp;nbsp;</p></td> <td width=”111″ valign=”top”><p>Carrom</p></td> <td width=”115″ valign=”top”><p>Bombay Arts &amp;amp; Sports</p></td> <td width=”234″ valign=”top”><p>Gaddam Neha, Kadam Shreyas, Malla Adarsh<br /> &amp;amp; Sawant Sail<br /> Reveived I Prize</p></td> </tr> <tr> <td width=”81″ valign=”top”><p>&amp;nbsp;</p></td> <td width=”111″ valign=”top”><p>Chess</p></td> <td width=”115″ valign=”top”><p>Bombay Arts &amp;amp; Sports</p></td> <td width=”234″ valign=”top”><p>Dicholkar Diti<br /> &amp;amp; Pol Prathmesh received I Prize</p></td> </tr> <tr> <td width=”81″ valign=”top”><p>&amp;nbsp;</p></td> <td width=”111″ valign=”top”><p>&amp;nbsp;</p></td> <td width=”115″ valign=”top”><p>I.E.S</p></td> <td width=”234″ valign=”top”><p>Malla Adarsh- I Prize and Gold medal</p></td> </tr> <tr> <td width=”81″ valign=”top”><p>&amp;nbsp;</p></td> <td width=”111″ valign=”top”><p>75m Running</p></td> <td width=”115″ valign=”top”><p> M.S.B Scout &amp;amp; Guide</p></td> <td width=”234″ valign=”top”><p>Haldankar Anushka &amp;amp; Pal Suraj- I Prize</p></td> </tr> <tr> <td width=”81″ valign=”top”><p>&amp;nbsp;</p></td> <td width=”111″ valign=”top”><p>Langadi</p></td> <td width=”115″ valign=”top”><p> —-“——</p></td> <td width=”234″ valign=”top”><p>Kadam Tejal &amp;amp; Kadam Sahil- I Prize</p></td> </tr> <tr> <td width=”81″ valign=”top”><p>2012</p></td> <td width=”111″ valign=”top”><p>Carrom</p></td> <td width=”115″ valign=”top”><p>Care Foundation</p></td> <td width=”234″ valign=”top”><p>Gaddam Neha,Malla Adarsh,Kadam Prathmesh received gold medals</p></td> </tr> <tr> <td width=”81″ valign=”top”><p>&amp;nbsp;</p></td> <td width=”111″ valign=”top”><p>&amp;nbsp;</p></td> <td width=”115″ valign=”top”><p>Mumbai Sports</p></td> <td width=”234″ valign=”top”><p>Gaddam Neha-Gold medal</p></td> </tr> <tr> <td width=”81″ valign=”top”><p>&amp;nbsp;</p></td> <td width=”111″ valign=”top”><p>Chess</p></td> <td width=”115″ valign=”top”><p>I.E.S</p></td> <td width=”234″ valign=”top”><p>Chaudhary Vaibhavi- Gold medal &amp;amp; Trophy</p></td> </tr> <tr> <td width=”81″ valign=”top”><p>&amp;nbsp;</p></td> <td width=”111″ valign=”top”><p>Gymnastics VT</p></td> <td width=”115″ valign=”top”><p>I.E.S</p></td> <td width=”234″ valign=”top”><p>Walavalkar Yash- Gold medal</p></td> </tr> <tr> <td width=”81″ valign=”top”><p>&amp;nbsp;</p></td> <td width=”111″ valign=”top”><p>400 m Running</p></td> <td width=”115″ valign=”top”><p>I.E.S</p></td> <td width=”234″ valign=”top”><p>Inpure Tanvi- I Prize</p></td> </tr> <tr> <td width=”81″ valign=”top”><p>&amp;nbsp;</p></td> <td width=”111″ valign=”top”><p>Long Jump</p></td> <td width=”115″ valign=”top”><p>—-“—-</p></td> <td width=”234″ valign=”top”><p>Yadav Ashutosh- I Prize</p></td> </tr> <tr> <td width=”81″ valign=”top”><p>&amp;nbsp;</p></td> <td width=”111″ valign=”top”><p>Shot Put</p></td> <td width=”115″ valign=”top”><p>——“—–</p></td> <td width=”234″ valign=”top”><p>Chaudhari Pratik-I Prize</p></td> </tr> <tr> <td width=”81″ valign=”top”><p>&amp;nbsp;</p></td> <td width=”111″ valign=”top”><p>Carrom</p></td> <td width=”115″ valign=”top”><p>I.E.S</p></td> <td width=”234″ valign=”top”><p>The school received ‘Nirgudkar Foundation Trophy’</p></td> </tr> <tr> <td width=”81″ valign=”top”><p>&amp;nbsp;</p></td> <td width=”111″ valign=”top”><p>Madhav Mantri Cricket Tournament</p></td> <td width=”115″ valign=”top”><p>I.E.S</p></td> <td width=”234″ valign=”top”><p>The school received ‘Late Dr. Harish Ram Nayak Rotating Trophy’</p></td> </tr> <tr> <td width=”81″ valign=”top”><p>&amp;nbsp;</p></td> <td width=”111″ valign=”top”><p>Kho-Kho</p></td> <td width=”115″ valign=”top”><p>I.E.S</p></td> <td width=”234″ valign=”top”><p>Won finals and received a Trophy</p></td> </tr> <tr> <td width=”81″ valign=”top”><p>&amp;nbsp;</p></td> <td width=”111″ valign=”top”><p>Cricket</p></td> <td width=”115″ valign=”top”><p>District Krida Adhikari</p></td> <td width=”234″ valign=”top”><p>Runner Up Award</p></td> </tr> <tr> <td width=”81″ valign=”top”><p> </p></td> <td width=”111″ valign=”top”><p>Foot Ball</p></td> <td width=”115″ valign=”top”><p>I.E.S</p></td> <td width=”234″ valign=”top”><p>Runner Up Award</p></td> </tr> <tr> <td width=”81″ valign=”top”><p>&amp;nbsp;</p></td> <td width=”111″ valign=”top”><p>Lazim</p></td> <td width=”115″ valign=”top”><p>Sahashaley Upakram</p></td> <td width=”234″ valign=”top”><p>I Prize</p></td> </tr> </table> <br /></td> </tr> </table> <p>&amp;nbsp;</p> </div> </ body > </ html ></code>
d) Infrastructure page should highlighting the available resources of the school.
For Infrastructure Page:  Infra.html
<code>
<html><head> <title>IES New English School, Bandra , Mumbai</title> </head> <body bgcolor=”lightgreen” > Infrastructure Page <div> <h1>Infrastructure </h1> <table width=”596″ border=”0″> <tr> <td width=”590″><table width=”539″ height=”47″ border=”0″ align=”center” cellpadding=”0″ cellspacing=”0″> <tbody> <tr> <th width=”520″ height=”45″ scope=”col”><p align=”left”>     Admission-  <br /> <br /> 1] Admission is open to all irrespective caste, creed and religion.<br /> 2] Applications are available in the office<br /> 3] The necessary documents such as L.C, latest progress report from the previous school etc. should be attached with the form.<br /> 4] Admissions will be confirmed only after the interview of the student and payment of fees.    </p> <p align=”left”> <strong>Facilities</strong>-  <br /> <br /> 1] well lighted and ventilated classrooms<br /> <br /> 2] A computer Lab with individual computer for every student<br /> <br /> 3] Well equipped Laboratories for Physics, Chemistry and Biology<br /> <br /> 4] Audio-Visual room<br /> <br /> 5] Library with treasure of books<br /> <br /> 6] Specious play ground<br /> <br /> 7] Auditorium with well equipped technology<br /> <br /> 8] A healthy canteen service<br /> <br /> 9] Arts and Spots Academy with well experienced coaches<br /> <br /> 10] Art room for showing creativity?<br /> <br /> 11] Introduction of new subjects- <br /> a] Technical with equipped lab <br /> b] V.G [Vocational Guidance] with expert councilors.<br /> <br /> 12] Well qualified staff<br /> <br /> 13] Personal attention <a name=”_GoBack” id=”_GoBack”></a></p></th> </tr> </tbody> </table> <br /></td> </tr> </table> <p>&amp;nbsp;</p> </div> </body> </html></code>
e) Contact us page should provide information about the school address and contact details.
For Contact Us Page:  Contact.html
<code>
<HTML >
<HEAD >
<TITLE > New Document </TITLE >
</HEAD >
<BODY bgcolor=”lightgreen” >
Contact Page
<center > <h1 > <u > Contact Us</u > </h1 > <center >
<table align=”center” >
<tr >
<tr > <img src=”contact.jpg” alt=”Image” width=”600px” height=”350px”/ > </td >
</tr >
</table >
</BODY >
</HTML >
</code>
f ) Feedback page should have a feedback form consisting of text box, radio buttons, list boxes etc. This page should get the information from the site visitors about various aspects of schools website. You must use JavaScript to check that all the required fields are entered by the visitor.
For Feedback Page:  <strong>Feedback.html</strong>
<code>
<html>
<head>
<title>Feedback form</title>
</head>
<body bgcolor=”lightgreen” >
Feedback Page
<h1>Website feedback form</h1>
<div>
<div><div><div class=”field-item even” property=”content:encoded”><p>Our website was recently redesigned. Please let us know how we can improve your experience by filling in this form.</p>
</div></div></div><div><div><div class=”field-item even”><p><strong>Information and privacy:</strong></p></div></div></div><form enctype=”multipart/form-data” action=”/school-environment-enterprise-development/website-feedback-form” method=”post” id=”webform-client-form-236″ accept-charset=”UTF-8″><div><div>
<label for=”edit-submitted-name”>First name </label>
<input type=”text” id=”edit-submitted-name” name=”submitted[name]” value=”" size=”60″ maxlength=”128″ />
</div>
<div>
<label for=”edit-submitted-last-name”>Last name </label>
<input type=”text” id=”edit-submitted-last-name” name=”submitted[last_name]” value=”" size=”60″ maxlength=”128″ />
</div>
<div>
<label for=”edit-submitted-email”>Email </label>
<input type=”email” id=”edit-submitted-email” name=”submitted[email]” size=”60″ />
</div>
<div>
<div>
<div>
<label for=”edit-submitted-who-are-you-select”>Who are you? <abbr title=”This field is required.”>*  (required) </abbr> </label>
<select id=”edit-submitted-who-are-you-select” name=”submitted[who_are_you][select]“><option value=”" selected=”selected”>- Select -</option><option value=”1″>Prospective student</option><option value=”2″>Undergrad student</option><option value=”3″>Graduate student</option><option value=”4″>Staff</option><option value=”5″>Faculty</option><option value=”6″>Alumni</option><option value=”select_or_other”>Other…</option></select>
</div>
<div>
<label for=”edit-submitted-who-are-you-other”>Who are you? Other… </label>
<input type=”text” id=”edit-submitted-who-are-you-other” name=”submitted[who_are_you][other]” value=”" size=”60″ maxlength=”128″ />
</div>
</div>
</div>
<input type=”hidden” name=”details[sid]” />
<input type=”hidden” name=”details[page_num]” value=”1″ />
<input type=”hidden” name=”details[page_count]” value=”1″ />
<input type=”hidden” name=”details[finished]” value=”0″ />
<input type=”hidden” name=”form_build_id” value=”form-qjLa24rqko-g3tMMntC-5NRTPS4SnDNwWsDBT9KOaJY” />
<input type=”hidden” name=”form_id” value=”webform_client_form_236″ />
<div class=’jfhtml’><p> <strong>What is your opinion of the site? </p> <p> Please rate the following aspects </p></div>
<div class=’error-message’ id=’hdeb2_2453_error’></div>
<fieldset class=’jfradio’ id=’hdeb2_2453′>
<div class=’control-group’>
<legend id=”hdeb2_2453_label”>Look and feel</legend>
<div class=’controls’>
<label class=’radio’ for=’hdeb2_2453_0′>
<input checked=checked value=’Good’ id=’hdeb2_2453_0′ name=’hdeb2′ type=’radio’ />
Good
</label>
<label class=’radio’ for=’hdeb2_2453_1′>
<input value=’Average’ id=’hdeb2_2453_1′ name=’hdeb2′ type=’radio’ />
Average
</label>
<label class=’radio’ for=’hdeb2_2453_2′>
<input value=’Poor’ id=’hdeb2_2453_2′ name=’hdeb2′ type=’radio’ />
Poor
</label>
<span class=’help-block’ id=’hdeb2_2453_error’>
</div>
</div>
</fieldset>
<div></div>
<div class=’error-message’ id=’h5e77_2454_error’></div>
<fieldset class=’jfradio’ id=’h5e77_2454′>
<div class=’control-group’>
<legend id=”h5e77_2454_label”>Ease of use</legend>
<div class=’controls’>
<label class=’radio’ for=’h5e77_2454_0′>
<input checked=checked value=’Good’ id=’h5e77_2454_0′ name=’h5e77′ type=’radio’ />
Good
</label>
<label class=’radio’ for=’h5e77_2454_1′>
<input value=’Average’ id=’h5e77_2454_1′ name=’h5e77′ type=’radio’ />
Average
</label>
<label class=’radio’ for=’h5e77_2454_2′>
<input value=’Poor’ id=’h5e77_2454_2′ name=’h5e77′ type=’radio’ />
Poor
</label>
<span class=’help-block’ id=’h5e77_2454_error’>
</div>
</div>
</fieldset>
<div></div>
<div class=’error-message’ id=’h99b4_2455_error’></div>
<fieldset class=’jfradio’ id=’h99b4_2455′>
<div class=’control-group’>
<legend id=”h99b4_2455_label”>Searching facilities</legend>
<div class=’controls’>
<label class=’radio’ for=’h99b4_2455_0′>
<input checked=checked value=’Good’ id=’h99b4_2455_0′ name=’h99b4′ type=’radio’ />
Good
</label>
<label class=’radio’ for=’h99b4_2455_1′>
<input value=’Average’ id=’h99b4_2455_1′ name=’h99b4′ type=’radio’ />
Average
</label>
<label class=’radio’ for=’h99b4_2455_2′>
<input value=’Poor’ id=’h99b4_2455_2′ name=’h99b4′ type=’radio’ />
Poor
</label>
<span class=’help-block’ id=’h99b4_2455_error’>
</div>
</div>
</fieldset>
<div></div>
<div class=’error-message’ id=’h94b8_2456_error’></div>
<fieldset class=’jfradio’ id=’h94b8_2456′>
<div class=’control-group’>
<legend id=”h94b8_2456_label”>Overall</legend>
<div class=’controls’>
<label class=’radio’ for=’h94b8_2456_0′>
<input value=’Good’ id=’h94b8_2456_0′ name=’h94b8′ type=’radio’ />
Good
</label>
<label class=’radio’ for=’h94b8_2456_1′>
<input checked=checked value=’Average’ id=’h94b8_2456_1′ name=’h94b8′ type=’radio’ />
Average
</label>
<label class=’radio’ for=’h94b8_2456_2′>
<input value=’Poor’ id=’h94b8_2456_2′ name=’h94b8′ type=’radio’ />
Poor
</label>
<label class=’radio’ for=’h94b8_2456_3′>
<input value=’No comment’ id=’h94b8_2456_3′ name=’h94b8′ type=’radio’ />
No comment
</label>
<span class=’help-block’ id=’h94b8_2456_error’>
</div>
</div>
</fieldset>
<div>
<label for=”edit-submitted-comments”>Comments </label>
<div><textarea id=”edit-submitted-comments” name=”submitted[comments]” cols=”60″ rows=”5″></textarea></div>
</div>
<div><input type=”submit” name=”op” value=”Submit” /></div></div></form><span property=”dc:title” content=”Website feedback form”> </div>
</body>
</html>
</code>
g) Write a program using VBscipt that adds only diagonal elements of two matrices. The program should be efficient.
<code>
hh’vb script program to find sum of diagonal elements in the given matrix ‘
declare double dimentional array
dim a(2,2)
dim sum,k sum=0 k=0
for i=0 to ubound(a,1)
for j=0 to ubound(a,2)
a(i,j)=cint(inputbox(“enter elements”))
next
sum=sum+a(i,k)
k=k+1
next
msgbox sum
</code>
Screen Shots:
ignou.nisecomputers.com
MCSL 016 solved assignment 2014-2015
ignou.nisecomputers.com